P21_049 - 49. (a) From problem #43, we have Ntotal = 2100 =...

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49. (a) From problem #43, we have N total =2 100 =1 . 27 × 10 30 microstates. (b) Using Eq. 21-18, we fnd W N total = ³ 100! (50!)(50!) ´ 1 . 27 × 10 30 = 12611418068195524166851562157 158456325028528675187087900672 =0 . 079589 8 . 0% . (c) Similarly, ±or n 1 =48and n 2 =52weobtain W N total = ³ 100! (48!)(52!) ´ 1 . 27 × 10 30 = 23301639718762469237395420275 316912650057057350374175801344 . 073527 7 . 4% . (d) With n 1 =52and n 2 = 48, we obtain the same result as in part (c). (e) For
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