Unformatted text preview: nRT ln 8 3 which yields (for T = 300 K and T = 800 K) the result Q H = 25 . 5 × 10 3 J. (b) The net work is the net heat ( Q 1 + Q 2 + Q 3 ). We ±nd Q 3 from nC p ( T − T ) = − 20 . 8 × 10 3 J. Thus, W = 4 . 73 × 10 3 J. (c) Using Eq. 219, we ±nd that the eﬃciency is ε =  W   Q H  = 4 . 73 × 10 3 25 . 5 × 10 3 = 0 . 185 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Work, Heat

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