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Unformatted text preview: nRT ln 8 3 which yields (for T = 300 K and T = 800 K) the result Q H = 25 . 5 10 3 J. (b) The net work is the net heat ( Q 1 + Q 2 + Q 3 ). We nd Q 3 from nC p ( T T ) = 20 . 8 10 3 J. Thus, W = 4 . 73 10 3 J. (c) Using Eq. 219, we nd that the eciency is =  W   Q H  = 4 . 73 10 3 25 . 5 10 3 = 0 . 185 ....
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 Fall '08
 SPRUNGER
 Physics, Work, Heat

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