P21_057 - − 1 400 K = 0 217 J(d ∆ S =(260 J(1 360 K −...

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57. The change in entropy in transferring a certain amount of heat Q from a heat reservoir at T 1 to another one at T 2 is ∆ S =∆ S 1 +∆ S 2 = Q (1 /T 2 1 /T 1 ) . (a) ∆ S = (260 J)(1 / 100 K 1 / 400 K) = 1 . 95 J . (b) ∆ S = (260 J)(1 / 200 K 1 / 400 K) = 0 . 650 J . (c) ∆ S = (260 J)(1 / 300 K
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Unformatted text preview: − 1 / 400 K) = 0 . 217 J . (d) ∆ S = (260 J)(1 / 360 K − 1 / 400 K) = 0 . 072 J . (e) We see that as the temperature diFerence between the two reservoirs decreases, so does the change in entropy....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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