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Unformatted text preview: constantvolume step). Using Eq. 2014 and Eq. 2016, we have W = nRT H ln V max V min + p min ( V min V max ) where (by the gas law in ratio form, as illustrated in Sample Problem 201) the volume ratio is V max V min = T H T L = 600 K 300 K = 2 . Thus, the net work is W = nRT H ln 2 + p min V min 1 V max V min = nRT H ln 2 + nRT L (1 2) = nR ( T H ln 2 T L ) = (1 mol) 8 . 31 J mol K ((600 K) ln2 (300 K)) = 9 . 6 10 2 J . (c) Eq. 219 gives = W Q H = 0 . 134 13% ....
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 Fall '08
 SPRUNGER
 Physics, Heat

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