Unformatted text preview: = mc I ln( T 4 /T 3 ) = mc I ln( T 1 /T 2 ) = − mc I ln( T 2 /T 1 ). Thus the net entropy change for the water drop is ∆ S = ∆ S 12 + ∆ S 23 + ∆ S 34 = m ( c w − c I ) ln µ T 2 T 1 ¶ − mL F T 2 = (1 . 00 g)(4 . 19 J / g · K − 2 . 22 J / g · K) ln µ 273 K 268 K ¶ − (1 . 00 g)(333 J / g) 273 K = − 1 . 18 J / K ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Mass

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