P22_003 - F = m 1 a 1 = k | q 1 || q 2 | r 2 = 8 99 × 10 9...

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3. (a) With a understood to mean the magnitude of acceleration, Newton’s second and third laws lead to m 2 a 2 = m 1 a 1 = m 2 = ( 6 . 3 × 10 7 kg )( 7 . 0m / s 2 ) 9 . 0m / s 2 =4 . 9 × 10 7 kg . (b) The magnitude of the (only) force on particle 1 is
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Unformatted text preview: F = m 1 a 1 = k | q 1 || q 2 | r 2 = ( 8 . 99 × 10 9 ) | q | 2 . 0032 2 . Inserting the values for m 1 and a 1 (see part (a)) we obtain | q | = 7 . 1 × 10 − 11 C ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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