10. There is no equilibrium position forq3betweenthe two Fxed charges, because it is being pulled by oneand pushed by the other (sinceq1andq2have di±erent signs); in this region this means the two forcearrows onq3are in the same direction and cannot cancel. It should also be clear that o±-axis (with theaxis deFned as that which passes through the two Fxed charges) there are no equilibrium positions. Onthe semi-inFnite region of the axis which is nearestq2and furthest fromq1an equilibrium position forq3cannot be found because|q1|<|q2|and the magnitude of force exerted byq2is everywhere (in thatregion) stronger than that exerted byq1onq3. Thus, we must look in the semi-inFnite region of the
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.