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Unformatted text preview: q  ) ( Q ) a 2 cos 45 = 1 4 Q 2 2 a 2 2  q  Q a 2 1 2 which (upon requiring F x = 0) leads to  q  = Q/ 2 2 or q = Q 2 2 . (b) The net force on q , examined along the y axis is F y = 1 4 q 2 (2 d ) 2 2 (  q  ) ( Q ) a 2 sin 45 = 1 4 q 2 2 a 2 2  q  Q a 2 1 2 which (if we demand F y = 0) leads to q = 2 Q 2 which is inconsistent with the result of part (a). Thus, we are unable to construct an equilibrium conguration with this geometry, where the only forces acting are given by Eq. 221....
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 Fall '08
 SPRUNGER
 Physics, Force

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