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Unformatted text preview: )(2 qQ/h 2 ), at a distance L/ 2 from the bearing. This torque is positive. The equation for rotational equilibrium is 1 4 qQ h 2 L 2 W x L 2 + 1 4 2 qQ h 2 L 2 = 0 . The solution for x is x = L 2 1 + 1 4 qQ h 2 W . (b) If N is the magnitude of the upward force exerted by the bearing, then Newtons second law (with zero acceleration) gives W 1 4 qQ h 2 1 4 2 qQ h 2 N = 0 . We solve for h so that N = 0. The result is h = r 1 4 3 qQ W ....
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 Fall '08
 SPRUNGER
 Physics, Charge, Force

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