P22_021 - 9 N m 2 / C 2 = 3 . 2 10 19 C . (b) Let N be the...

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21. (a) The magnitude of the force between the (positive) ions is given by F = ( q )( q ) 4 πε 0 r 2 = k q 2 r 2 where q is the charge on either of them and r is the distance between them. We solve for the charge: q = r r F k =(5 . 0 × 10 10 m) s 3 . 7 × 10 9 N 8 . 99 × 10
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Unformatted text preview: 9 N m 2 / C 2 = 3 . 2 10 19 C . (b) Let N be the number of electrons missing from each ion. Then, Ne = q , or N = q e = 3 . 2 10 19 C 1 . 6 10 19 C = 2 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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