P22_024 - 24. With F = me g , Eq. 22-1 leads to 1.60 1019 C...

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24. With F = m e g , Eq. 22-1 leads to r 2 = ke 2 m e g = ³ 8 . 99 × 10 9 N · m 2 / C 2 ´ ( 1 . 60 × 10 19 C ) 2 (9 . 11 × 10 31 kg) (9 . 8m / s 2 ) which leads to r =5 . 1 m. The second electron should be below the frst one, so that the repulsive Force
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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