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Unformatted text preview: ~ F 3 net = 0. Writing r 3 1 = x and r 3 2 = x . 20 m, we equate  ~ F 3 1  and  ~ F 3 2  , and after canceling common factors, arrive at  q 1  x 2 = q 2 ( x . 2) 2 . This can be further simpliFed to ( x . 2) 2 x 2 = q 2  q 1  = 1 2 . Taking the (positive) square root and solving, we obtain x = 0 . 68 m. If one takes the negative root and solves, one Fnds the location where the net force would be zero if q 1 and q 2 were of like sign (which is not the case here)....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Charge, Force

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