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Unformatted text preview: addition becomes (0 . 518 6 37 ) + (0 . 518 6 37 ) = (0 . 829 6 ) . Therefore, the net force is 0 . 829 N in the + x direction. (b) Switching the sign of Q 2 amounts to reversing the direction of its force on q . Consequently, we have (0 . 518 6 37 ) + (0 . 518 6 143 ) = (0 . 621 6 90 ) . Therefore, the net force is 0 . 621 N in the y direction....
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 Fall '08
 SPRUNGER
 Physics, Charge, Force

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