Unformatted text preview: addition becomes (0 . 518 6 − 37 ◦ ) + (0 . 518 6 37 ◦ ) = (0 . 829 6 ◦ ) . Therefore, the net force is 0 . 829 N in the + x direction. (b) Switching the sign of Q 2 amounts to reversing the direction of its force on q . Consequently, we have (0 . 518 6 − 37 ◦ ) + (0 . 518 6 − 143 ◦ ) = (0 . 621 6 − 90 ◦ ) . Therefore, the net force is 0 . 621 N in the − y direction....
View
Full
Document
 Fall '08
 SPRUNGER
 Physics, Charge, Force

Click to edit the document details