P22_043 - Q = 82 . 9 C. (b) Now, we require that the x...

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43. (a) For the net force to be in the + x direction, the y components of the individual forces must cancel. The angle of the force exerted by the q 1 =40 µ Cchargeon q =20 µ Cis45 , and the angle of force exerted on q by Q is at θ where θ =tan 1 µ 2 . 0 3 . 0 =33 . 7 . Therefore, cancellation of y components requires k q 1 q ( 0 . 02 2 ) 2 sin 45 = k | Q | q ( 0 . 03 2 +0 . 02 2 ) 2 sin θ from which we obtain | Q | =82 . 9 µ C. Charge Q is “pulling” on q , so (since q> 0) we conclude
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Unformatted text preview: Q = 82 . 9 C. (b) Now, we require that the x components cancel, and we note that in this case, the angle of force on q exerted by Q is + (it is repulsive, and Q is positive-valued). Therefore, k q 1 q ( . 02 2 ) 2 cos 45 = k Q q ( . 03 2 + 0 . 02 2 ) 2 cos from which we obtain Q = 55 . 2 C....
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