P22_049

# P22_049 - 49. In experiment 1, sphere C ﬁrst touches...

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Unformatted text preview: 49. In experiment 1, sphere C ﬁrst touches sphere A, and they divided up their total charge (Q/2 plus Q) equally between them. Thus, sphere A and sphere C each acquired charge 3Q/4. Then, sphere C touches B and those spheres split up their total charge (3Q/4 plus −Q/4) so that B ends up with charge equal to Q/4. The force of repulsion between A and B is therefore F1 = k 3Q 4 Q 4 d2 at the end of experiment 1. Now, in experiment 2, sphere C ﬁrst touches B which leaves each of them with charge Q/8. When C next touches A, sphere A is left with charge 9Q/16. Consequently, the force of repulsion between A and B is F2 = k 9Q 16 Q 8 d2 at the end of experiment 2. The ratio is F2 = F1 9 16 3 4 1 8 1 4 = 0.375 . ...
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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