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Unformatted text preview: 49. In experiment 1, sphere C ﬁrst touches sphere A, and they divided up their total charge (Q/2 plus Q)
equally between them. Thus, sphere A and sphere C each acquired charge 3Q/4. Then, sphere C touches
B and those spheres split up their total charge (3Q/4 plus −Q/4) so that B ends up with charge equal
to Q/4. The force of repulsion between A and B is therefore F1 = k 3Q
4 Q
4 d2 at the end of experiment 1. Now, in experiment 2, sphere C ﬁrst touches B which leaves each of them
with charge Q/8. When C next touches A, sphere A is left with charge 9Q/16. Consequently, the force
of repulsion between A and B is
F2 = k 9Q
16 Q
8 d2 at the end of experiment 2. The ratio is
F2
=
F1 9
16
3
4 1
8
1
4 = 0.375 . ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Charge

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