P23_018 - R ) 2 + R 2 ) 3 / 2 Simplifying, we obtain q 1 q...

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18. We use Eq. 23-3, assuming both charges are positive. E left ring = E right ring evaluated at P q 1 R 4 πε 0 ( R 2 + R 2 ) 3 / 2 = q 2 (2 R ) 4 πε 0 ((2
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Unformatted text preview: R ) 2 + R 2 ) 3 / 2 Simplifying, we obtain q 1 q 2 = 2 2 5 3 / 2 . 51 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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