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Unformatted text preview: 22. We ﬁnd the maximum by diﬀerentiating Eq. 2316 and setting the result equal to zero.
d
dz
√
which leads to z = R/ 2. qz
3/ 2 4πε0 (z 2 + R2 ) = R 2 − 2z 2
q
=0
4πε0 (z 2 + R2 )5/2 ...
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 Fall '08
 SPRUNGER
 Physics

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