Unformatted text preview: 22. We ﬁnd the maximum by diﬀerentiating Eq. 2316 and setting the result equal to zero.
d
dz
√
which leads to z = R/ 2. qz
3/ 2 4πε0 (z 2 + R2 ) = R 2 − 2z 2
q
=0
4πε0 (z 2 + R2 )5/2 ...
View
Full
Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

Click to edit the document details