P23_027 - = / 2 . We want to solve for the value of z such...

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27. At a point on the axis of a uniformly charged disk a distance z above the center of the disk, the magnitude of the electric Feld is E = σ 2 ε 0 · 1 z z 2 + R 2 ¸ where R is the radius of the disk and σ is the surface charge density on the disk. See Eq. 23-26. The magnitude of the Feld at the center of the disk ( z =0)is E c
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Unformatted text preview: = / 2 . We want to solve for the value of z such that E/E c = 1 / 2. This means 1 z z 2 + R 2 = 1 2 = z z 2 + R 2 = 1 2 . Squaring both sides, then multiplying them by z 2 + R 2 , we obtain z 2 = ( z 2 / 4)+( R 2 / 4). Thus, z 2 = R 2 / 3 and z = R/ 3....
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