This preview shows page 1. Sign up to view the full content.
31. We combine Eq. 239 and Eq. 2328 (in absolute values).
F
=

q

E
=

q

µ
p
2
πε
0
z
3
¶
=
2
kep
z
3
where we use Eq. 225 in the last step. Thus, we obtain
F
=
2
(
8
.
99
×
10
9
N
·
m
2
/
C
2
)(
1
.
60
×
10
−
19
C
)(
3
.
6
×
10
−
29
C
·
m
)
(25
×
10
−
9
m)
3
which yields a force of magnitude 6
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Force

Click to edit the document details