P23_039 - kg) (1 . 60 10 19 C)(1 . 5 10 8 s) 2 = 1 . 10 3 N...

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39. (a) We use ∆ x = v avg t = vt/ 2: v = 2∆ x t = 2(2 . 0 × 10 2 m) 1 . 5 × 10 8 s =2 . 7 × 10 6 m / s . (b) We use ∆ x = 1 2 at 2 and E = F/e = ma/e : E = ma e = 2∆ xm et 2 = 2(2 . 0 × 10 2 m)(9 . 11 × 10 31
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Unformatted text preview: kg) (1 . 60 10 19 C)(1 . 5 10 8 s) 2 = 1 . 10 3 N / C ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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