P23_040

# P23_040 - v x = v x in this problem(that is a x = 0 we...

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40. We assume there are no forces or force-components along the x direction. We combine Eq. 23-28 with Newton’s second law, then use Eq. 4-21 to determine time t followed by Eq. 4-23 to determine the Fnal velocity (with g replaced by the a y of this problem); for these purposes, the velocity components given in the problem statement are re-labeled as v 0 x and v 0 y respectively. (a) We have ~a = q ~ E m = ( e m ) ~ E which leads to ~a = µ 1 . 60 × 10 19 C 9 . 11 × 10 31 kg ¶µ 120 N C ˆ j= 2 . 1 × 10 13 m / s 2 ˆ j . (b) Since
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Unformatted text preview: v x = v x in this problem (that is, a x = 0), we obtain t = ∆ x v x = . 020 m 1 . 5 × 10 5 m / s = 1 . 3 × 10 − 7 s v y = v y + a y t = 3 . × 10 3 m / s + ( − 2 . 1 × 10 13 m / s 2 )( 1 . 3 × 10 − 7 s ) which leads to v y = − 2 . 8 × 10 6 m/s. Therefore, in unit vector notation (with SI units understood) the Fnal velocity is ~v = 1 . 5 × 10 5 ˆ i − 2 . 8 × 10 6 ˆ j ....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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