P23_044 - U (180 ) U (0) = 2 pE = 2 ( 9 . 30 10 15 ) (1100)...

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44. (a) The magnitude of the dipole moment is p = qd = ( 1 . 50 × 10 9 C )( 6 . 20 × 10 6 m ) =9 . 30 × 10 15 C · m . (b) Following the solution to part (c) of Sample Problem 23-5, we ±nd
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Unformatted text preview: U (180 ) U (0) = 2 pE = 2 ( 9 . 30 10 15 ) (1100) = 2 . 05 10 11 J ....
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