50.(a) From Eq. 23-38 (and the facts thatˆi·ˆi=1andˆj·ˆi = 0), the potential energy isU=−~p·~E=−[(3.00ˆi+4.00ˆj)(1.24×10−30C·m)]·[(4000 N/C)ˆi]=−1.49×10−26J.(b) From Eq. 23-34 (and the facts thatˆi×ˆi=0andˆj×ˆi=−ˆk), the torque is~τ=~p×~E=[(3.00ˆ.00ˆj)(1.24×10−30C·m)]×[(4000 N/C)ˆi]=(−1.98×10−26N·
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.