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Unformatted text preview: 54. Studying Sample Problem 233, we see that the ﬁeld evaluated at the center of curvature due to a charged
distribution on a circular arc is given by
E= λ
sin θ
4πε0 r θ /2 along the symmetry axis
−θ/2 where λ = q/ = q/rθ with θ in radians. Here is the length of the arc, given as
θ = /r = 4.0/2.0 = 2.0 rad. Thus, with q = 20 × 10−9 C, we obtain
E= q 1
sin θ
4πε0 r 1.0 rad = 38 N/C .
−1.0 rad = 4.0 m. Therefore, ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Charge

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