P23_054 - 54. Studying Sample Problem 23-3, we see that the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 54. Studying Sample Problem 23-3, we see that the field evaluated at the center of curvature due to a charged distribution on a circular arc is given by E= λ sin θ 4πε0 r θ /2 along the symmetry axis −θ/2 where λ = q/ = q/rθ with θ in radians. Here is the length of the arc, given as θ = /r = 4.0/2.0 = 2.0 rad. Thus, with q = 20 × 10−9 C, we obtain E= q 1 sin θ 4πε0 r 1.0 rad = 38 N/C . −1.0 rad = 4.0 m. Therefore, ...
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online