Unformatted text preview: q 2 (where x > d ), ~ E 1 points leFtward and ~ E 2 points rightward so the net feld in this range is ~ E net = ¯ ¯ ¯ ~ E 2 ¯ ¯ ¯ − ¯ ¯ ¯ ~ E 1 ¯ ¯ ¯ in the ˆ i direction . Although  q 1  > q 2 there is the possibility oF ~ E net = 0 since these points are closer to q 2 than to q 1 . Thus, we look For the zero net feld point in the x > d region: ¯ ¯ ¯ ~ E 1 ¯ ¯ ¯ = ¯ ¯ ¯ ~ E 2 ¯ ¯ ¯ 1 4 πε  q 1  x 2 = 1 4 πε q 2 ( x − d ) 2 which leads to x − d x = r q 2  q 1  = r 1 2 . ThereFore, x = d √ 2 √ 2 − 1 = 6 . 8 m specifes the position where ~ E net = 0 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Charge

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