P23_065 - 65. We denote the electron with subscript e and...

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Unformatted text preview: 65. We denote the electron with subscript e and the proton with p. From the figure to the right we see that Ee = Ep = e 4πε0 d 2 where d = 2.0 × 10−6 m. We note that the components along the y axis cancel during the vector summation. With k = 1/4πε0 and θ = 60◦ , the magnitude of the net electric field is obtained as follows: Enet ... .... .. .. .. .. .. .. Ep .. . .. .. .. θ .. x ........................................... . ... .. ... . . .. .. . .. .. θ . .. ... .. ... .. .. Enet . .. .... . . ... . .. .. .... . .. .. .. .. .. .. . . ..... .. .. ...... Ee ..... .. . .. . . y . .. .. .. .. . .. . • proton = 2 = 2 8.99 × 109 = 3.6 × 102 N/C . . θ . .. .. . .. .. . .. .. . .. .. . • electron Ex = 2Ee cos θ = .. .. e 4πε0 d2 cos θ = 2k N · m2 C2 e cos θ d2 (1.6 × 10−19 C) cos 60◦ (2.0 × 10−6 m)2 ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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