1. (a) The mass ﬂux is wdρv =(3 . 22 m)(1 . 04 m) ³ 1000 kg / m 3 ´ (0 . 207 m / s) = 693 kg / s . (b) Since water ﬂows only through area wd , the ﬂux through the larger area is still 693 kg / s. (c) Now the mass ﬂux is ( wd/ 2) ρv = (693 kg
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.