P24_001 - 3 1. (a) The mass ux is wdv = (3.22 m)(1.04 m)...

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1. (a) The mass flux is wdρv =(3 . 22 m)(1 . 04 m) ³ 1000 kg / m 3 ´ (0 . 207 m / s) = 693 kg / s . (b) Since water flows only through area wd , the flux through the larger area is still 693 kg / s. (c) Now the mass flux is ( wd/ 2) ρv = (693 kg
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