P24_002 - 2. The vector area A and the electric field E...

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Unformatted text preview: 2. The vector area A and the electric field E are shown on the diagram below. The angle θ between them is 180◦ − 35◦ = 145◦ , so the electric flux through the area is Φ = E · A = EA cos θ = (1800 N/C)(3.2 × 10−3 m)2 cos 145◦ = −1.5 × 10−2 N · m2 /C . . .. .. . .. ... ..... . . . . . ◦ .... . . . . . . . .. ...... .. ...... . .. . . .. ... .. ... . . . . ... .. .. . ... . . . .. .. . .. . . . . .. . ... . . . .. . . . . . .. . .. . . .. . .. .. .. .. .. .. . ... .. .... .. . .. .. .. .. .. .. .. . . .. .. .. .. ... ... . ..... .... ... A θ E 35 ...
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