P24_023 - 23 The electric field is radially outward from the central wire We want to find its magnitude in the region between the wire and the

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Unformatted text preview: 23. The electric field is radially outward from the central wire. We want to find its magnitude in the region between the wire and the cylinder as a function of the distance r from the wire. Since the magnitude of the field at the cylinder wall is known, we take the Gaussian surface to coincide with the wall. Thus, the Gaussian surface is a cylinder with radius R and length L, coaxial with the wire. Only the charge on the wire is actually enclosed by the Gaussian surface; we denote it by q . The area of the Gaussian surface is 2πRL, and the flux through it is Φ = 2πRLE . We assume there is no flux through the ends of the cylinder, so this Φ is the total flux. Gauss’ law yields q = 2πε0 RLE . Thus, q = 2π 8.85 × 10−12 C2 N · m2 (0.014 m)(0.16 m) 2.9 × 104 N/C = 3.6 × 10−9 C . ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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