P24_042 - 2 dr = e 4 a 2 1 4 a 3 Z a exp( 2 r/a ) r 2 dr =...

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42. (a) We note that the symbol “ e ” stands for the elementary charge in the manipulations below. From e = Z 0 ρ ( r )4 πr 2 dr = Z 0 A exp ( 2 r/a 0 )4 πr 2 dr = πa 3 0 A we get A = e/πa 3 0 . (b) The magnitude of the ±eld is E = q encl 4 πε 0 a 2 0 = 1 4 πε 0 a 2 0 µ e + Z a 0 0 ρ ( r )4 πr
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Unformatted text preview: 2 dr = e 4 a 2 1 4 a 3 Z a exp( 2 r/a ) r 2 dr = 5 e exp( 2) 4 a 2 . We note that E points radially outward....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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