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Unformatted text preview: 46. (a) From Gauss’ law,
E (r ) = 1 qencl
1 (4πρr3 /3)r
3 ε0 (b) The charge distribution in this case is equivalent to that of a whole sphere of charge density ρ plus
a smaller sphere of charge density −ρ which ﬁlls the void. By superposition
E (r ) = (−ρ)(r − a)
3 ε0 ...
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