P24_047 - 47 We use E(r = qencl 1 = 40 r2 40 r2 r(r)4r2 dr...

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47. We use E ( r )= q encl 4 πε 0 r 2 = 1 4 πε 0 r 2 Z r 0 ρ ( r )4 πr 2 dr to solve for ρ ( r ): ρ ( r )= ε 0 r 2 d dr [ r 2 E ( r )] =
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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