P24_059 - halF the side-length oF the cube). Thus, the...

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59. (a) The cube is totally within the spherical volume, so the charge enclosed is ρV cube = (500 × 10 9 )(0 . 040) 3 =3 . 2 × 10 11 C. By Gauss’ law, we fnd Φ = q enc 0 =3 . 6N · m 2 /C. (b) Now the sphere is totally contained within the cube (note that the radius oF the sphere is less than
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Unformatted text preview: halF the side-length oF the cube). Thus, the total charge is q enc V sphere = 4 . 5 10 10 C. By Gauss law, we fnd = q enc / = 51 N m 2 /C....
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