P24_066 - the net charge enclosed in a Gaussian surface...

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66. We use Eqs. 24-15, 24-16 and the superposition principle. (a) E = 0 in the region inside the shell. (b) E =(1 / 4 πε 0 )( q a /r 2 ) . (c) E =(1 / 4 πε 0 )( q a + q b ) /r 2 . (d) Since E =0for r<a the charge on the inner surface of the inner shell is always zero. The charge on the outer surface of the inner shell is therefore q a .S i n
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Unformatted text preview: the net charge enclosed in a Gaussian surface that lies in between the inner and outer surfaces of the outer shell is zero. Thus the inner surface of the outer shell must carry a charge q a , leaving the charge on the outer surface of the outer shell to be q b + q a ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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