P25_003 - 3. (a) When charge q moves through a potential...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 3. (a) When charge q moves through a potential difference ∆V , its potential energy changes by ∆U = q ∆V . In this case, ∆U = (30 C)(1.0 × 109 V) = 3.0 × 1010 J. (b) We equate the final kinetic energy 1 mv 2 of the automobile to the energy released by the lightning, 2 denoted by Ulightning . v= 2 Ulightning = m 2(3.0 × 1010 J) = 7.7 × 103 m/s . 1000 kg (c) We equate the energy required to melt mass m of ice to the energy released by the lightning: ∆U = mLF , where LF is the heat of fusion for ice. Thus, m= ∆U 3.0 × 1010 J = = 9.0 × 104 kg . LF 3.33 × 105 J/kg ...
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online