P25_015 - V x = k µ q 1 d 1 q 2 d 2 = q 4 πε µ 1 −...

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15. First, we observe that V ( x ) cannot be equal to zero for x>d .Infac t V ( x ) is always negative for x>d . Now we consider the two remaining regions on the x axis: x< 0and0 <x<d .F o r x< 0 the separation between q 1 andapo intonthe x axis whose coordinate is x is given by d 1 = x ; while the corresponding separation for q 2 is d 2 =
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Unformatted text preview: V ( x ) = k µ q 1 d 1 + q 2 d 2 ¶ = q 4 πε µ 1 − x + − 3 d − x ¶ = 0 to obtain x = − d/ 2. Similarly, for 0 < x < d we have d 1 = x and d 2 = d − x . Let V ( x ) = k µ q 1 d 1 + q 2 d 2 ¶ = q 4 πε µ 1 x + − 3 d − x ¶ = 0 and solve: x = d/ 4....
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