P25_016 - both negative). Thus, the potentials due to...

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16. Since according to the problem statement there is a point in between the two charges on the x axis where the net electric feld is zero, the felds at that point due to q 1 and q 2 must be directed opposite to each other. This means that q 1 and q 2 must have the same sign (i.e., either both are positive or
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Unformatted text preview: both negative). Thus, the potentials due to either oF them must be oF the same sign. ThereFore, the net electric potential cannot possibly be zero anywhere except at infnity....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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