P25_042 - 42. (a) The potential is V (r ) = = 1e 40 r 8.99...

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42. (a) The potential is V ( r )= 1 4 πε 0 e r = ³ 8 . 99 × 10 9 N · m 2 C 2 ´ (1 . 60 × 10 19 C) 5 . 29 × 10 11 m =27 . 2V . (b) The potential energy is U = eV ( r 27 . 2eV . (c) Since m e v 2 /r = e 2 / 4 0 r 2 , K = 1 2 mv 2 = 1 2 µ e 2 4 0 r = 1 2 V ( r 27 . 2 =13 . 6eV . (d) The energy required is
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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