P25_055 - 55(a The potential would be = 2 Qe 4Re e = = 4Re e k 40 Re 40 Re = 4(6.37 106 m(1.0 electron m2(1.6 1019 C electron 8.99 109 = Ve 0.12

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55. (a) The potential would be V e = Q e 4 πε 0 R e = 4 πR 2 e σ e 4 0 R e =4 e σ e k π (6 . 37 × 10 6 m)(1 . 0 electron / m 2 )( 1 . 6 × 10 19 C / electron) µ 8 . 99 × 10 9 N · m 2 C 2 = 0 . 12 V . (b) The electric feld is E = σ e ε 0 = V e R e = 0 . 12 V 6 . 37 × 10 6 m
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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