P25_063 - (4 πε r 2 for r> R Here R is the radius of...

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63. We imagine moving all the charges on the surface of the sphere to the center of the the sphere. Using Gauss’ law, we see that this would not change the electric Feld outside the sphere. The magnitude of the electric Feld E of the uniformly charged sphere as a function of r , the distance from the center of thesphere ,isthusg ivenby E ( r
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Unformatted text preview: (4 πε r 2 ) for r > R . Here R is the radius of the sphere. Thus, the potential V at the surface of the sphere (where r = R ) is given by V ( R ) = V ¯ ¯ ¯ ¯ r = ∞ + Z ∞ R E ( r ) dr = Z R ∞ q 4 πε r 2 dr = q 4 πε R = ³ 8 . 99 × 10 9 N · m 2 C 2 ´ ( 1 . 50 × 10 8 C ) . 160 m = 8 . 43 × 10 2 V ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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