82.(a) At the smallest center-to-center separationrminthe initial kinetic energyKiof the proton is entirelyconverted to the electric potential energy between the proton and the nucleus. Thus,Ki=14πε0eqleadrmin=82e240rmin.In solving forrminusing the eV unit, we note that a factor ofecancels in the middle line:rmin=82e240Ki=k82e24.80×106eV=µ8.99×109N·m2C2¶82(1.6×10−19C)4.80×106V=2.5×10−14m=25fm.It is worth recalling that a volt is a Newton
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.