P25_084 - B V A = q 4 1 p z 2 B + R 2 1 R ! where z B = 0 ....

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84. For a point on the axis of the ring the potential (assuming V 0as r →∞ )is V = q 4 πε 0 z 2 + R 2 where q =16 × 10 6 Cand R =0 . 030 m. Therefore, V
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Unformatted text preview: B V A = q 4 1 p z 2 B + R 2 1 R ! where z B = 0 . 040 m. The result is 1 . 92 10 6 V....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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