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Unformatted text preview: 19 m/s. (d) Using the Pythagorean theorem, we now have U i = 2 k qQ p d 2 + x 2 . Therefore, (with U A in this part equal to the negative of U A in the previous part) v = r 2 ( U i U A ) m = 2 v u u t k q Q m 1 d 1 p d 2 + x 2 . To simplify, the binomial theorem (Appendix E) is employed: 1 p d 2 + x 2 1 d 1 1 2 x 2 d 2 which leads to v x d r 2 k q Q md ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Energy, Kinetic Energy, Potential Energy

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