P26_017

# P26_017 - is q 2 = q q 1 , where C 2 is the capacitance o...

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17. The charge initially on the charged capacitor is given by q = C 1 V 0 ,where C 1 = 100 pF is the capacitance and V 0 = 50 V is the initial potential diference. A±ter the battery is disconnected and the second capacitor wired in parallel to the ²rst, the charge on the ²rst capacitor is q 1 = C 1 V ,where v =35Vis the new potential diference. Since charge is conserved in the process, the charge on the second capacitor
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Unformatted text preview: is q 2 = q q 1 , where C 2 is the capacitance o the second capacitor. Substituting C 1 V or q and C 1 V or q 1 , we obtain q 2 = C 1 ( V V ). The potential diference across the second capacitor is also V , so the capacitance is C 2 = q 2 V = V V V C 1 = 50 V 35 V 35 V (100 pF) = 3 pF ....
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