P26_019

# P26_019 - 19. (a) After the switches are closed, the...

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Unformatted text preview: 19. (a) After the switches are closed, the potential diﬀerences across the capacitors are the same and the two capacitors are in parallel. The potential diﬀerence from a to b is given by Vab = Q/Ceq , where Q is the net charge on the combination and Ceq is the equivalent capacitance. The equivalent capacitance is Ceq = C1 + C2 = 4.0 × 10−6 F. The total charge on the combination is the net charge on either pair of connected plates. The charge on capacitor 1 is q1 = C1 V = (1.0 × 10−6 F)(100 V) = 1.0 × 10−4 C and the charge on capacitor 2 is q2 = C2 V = (3.0 × 10−6 F)(100 V) = 3.0 × 10−4 C , so the net charge on the combination is 3.0 × 10−4 C − 1.0 × 10−4 C = 2.0 × 10−4 C. The potential diﬀerence is 2.0 × 10−4 C Vab = = 50 V . 4.0 × 10−6 F (b) The charge on capacitor 1 is now q1 = C1 Vab = (1.0 × 10−6 F)(50 V) = 5.0 × 10−5 C. (c) The charge on capacitor 2 is now q2 = C2 Vab = (3.0 × 10−6 F)(50 V) = 1.5 × 10−4 C. ...
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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