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Unformatted text preview: q is the original charge, conservation of charge yields q 1 + q 2 = q = C 1 V , where V is the original potential diFerence across capacitor 1. Solving the two equations q 1 C 1 = q 2 C eq and q 1 + q 2 = C 1 V for q 1 and q 2 , we nd q 2 = C 1 V q 1 and q 1 = C 2 1 V C eq + C 1 = C 2 1 V C 2 C 3 C 2 + C 3 + C 1 = C 2 1 ( C 2 + C 3 ) V C 1 C 2 + C 1 C 3 + C 2 C 3 . The charges on capacitors 2 and 3 are q 2 = q 3 = C 1 V q 1 = C 1 V C 2 1 ( C 2 + C 3 ) V C 1 C 2 + C 1 C 3 + C 2 C 3 = C 1 C 2 C 3 V C 1 C 2 + C 1 C 3 + C 2 C 3 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Capacitance, Charge

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