P26_027 - 27. (a) In the first case U = q 2 /2C , and in...

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Unformatted text preview: 27. (a) In the first case U = q 2 /2C , and in the second case U = 2(q/2)2 /2C = q 2 /4C. So the energy is now 4 . 0 J / 2 = 2. 0 J . (b) It becomes the thermal energy generated in the wire connecting the capacitors during the discharging process (although a small fraction of it is probably radiated away in the form of radio waves). ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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