P26_046 - 46. (a) We apply Gausss law with dielectric: q/0...

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46. (a) We apply Gauss’s law with dielectric: q/ε 0 = κEA , and solve for κ : κ = q ε 0 EA = 8 . 9 × 10 7 C ( 8 . 85 × 10 12 C 2 N · m 2 ) (1 . 4 × 10 6 V / m)(100 × 10 4 m 2 ) =7 . 2 . (b) The charge induced is
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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