P26_049 - 49(a With the potential difference equal to 600...

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Unformatted text preview: 49. (a) With the potential difference equal to 600 V, a capacitance of 2.5 × 10−10 F can only store energy equal to U = 1 CV 2 = 4.5 × 10−5 J. 2 (b) No, our result from part (a) is only about 20% of that needed to produce a spark. (c) Considering the charge as a constant, then voltage should be inversely proportional to the capacitance. Therefore, if the capacitance drops by a factor of ten, then we expect the voltage to increase by that same factor: Vf = 6000 V. (d) Now the energy stored is U = obtained in part (a). 1 2 2 Cf Vf = 4.5 × 10−4 J, a factor of ten greater than the value we (e) Yes, this new value of energy is nearly double that needed for a spark. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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