P26_049

# P26_049 - 49(a With the potential diﬀerence equal to 600...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 49. (a) With the potential diﬀerence equal to 600 V, a capacitance of 2.5 × 10−10 F can only store energy equal to U = 1 CV 2 = 4.5 × 10−5 J. 2 (b) No, our result from part (a) is only about 20% of that needed to produce a spark. (c) Considering the charge as a constant, then voltage should be inversely proportional to the capacitance. Therefore, if the capacitance drops by a factor of ten, then we expect the voltage to increase by that same factor: Vf = 6000 V. (d) Now the energy stored is U = obtained in part (a). 1 2 2 Cf Vf = 4.5 × 10−4 J, a factor of ten greater than the value we (e) Yes, this new value of energy is nearly double that needed for a spark. ...
View Full Document

## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online