P26_050

# P26_050 - (b) By Eq. 26-21, the energy stored is U = q 2 2...

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50. (a) We calculate the charged surface area of the cylindrical volume as follows: A =2 πrh + πr 2 =2 π (0 . 20 m)(0 . 10 m) + π (0 . 20 m) 2 =0 . 25 m 2 where we note from the Fgure that although the bottom is charged, the top is not. Therefore, th echa rg ei s q = σA = 0 . 50 µ
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Unformatted text preview: (b) By Eq. 26-21, the energy stored is U = q 2 2 C = ( 5 . 10 7 C ) 2 2 (35 10 12 ) = 3 . 6 10 3 J . (c) Our result is within a factor of three of that needed to cause a spark. Our conclusion is that it will probably not cause a spark; however, there is not enough of a safety factor to be sure....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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